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b^2-7b-44=0
a = 1; b = -7; c = -44;
Δ = b2-4ac
Δ = -72-4·1·(-44)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-15}{2*1}=\frac{-8}{2} =-4 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+15}{2*1}=\frac{22}{2} =11 $
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